(235⋅523)15109=(235⋅15⋅523⋅15)109=(23⋅3⋅52⋅5)109\displaystyle {({2^{3\over5}\cdot5^{2\over3}})^{15}\over10^9} = \displaystyle {({2^{{3\over5}\cdot15 }\cdot5^{{2\over3}\cdot15}})\over10^9} = \displaystyle {({2^{3\cdot 3}\cdot5^{2\cdot 5}}) \over10^9}109(253⋅532)15=109(253⋅15⋅532⋅15)=109(23⋅3⋅52⋅5)
29⋅510109=29⋅59⋅51109=(2⋅5)9⋅5109\displaystyle \frac{2^9 \cdot 5^{10} }{10^9} = \frac{2^9 \cdot 5^9 \cdot 5^1 }{10^9} = \frac{ {(2 \cdot 5) }^9 \cdot 5 }{10^9}10929⋅510=10929⋅59⋅51=109(2⋅5)9⋅5
109⋅5109=5\displaystyle { \frac{10^9 \cdot 5 }{10^9} = 5 }109109⋅5=5