Найдите корень уравнения
3x−11=19\displaystyle{ 3^{x-11} = \frac{1}{9} } 3x−11=91
3x−11=132\displaystyle{ 3^{x-11} = \frac{1}{3^2} } 3x−11=321
3x−11=32∗(−1)\displaystyle{ 3^{x-11} = 3^{2 *(-1)} } 3x−11=32∗(−1)
x−11=−2\displaystyle{ x-11 = -2 } x−11=−2
x=11−2\displaystyle{ x = 11-2 } x=11−2
x=9\displaystyle{x = 9}x=9