$V(АВСDA_1B_1C_1D_1)=AD·DC·DD1=666\\ {V(D_1ACD)=\displaystyle{S(ADC)·DD_1\over3}}\\ {S(ADC)=\displaystyle{AD·DC\over2}}\\ {V(D_1ACD) = \displaystyle{1\over2}\cdot{1\over3}AD·DC·DD_1 = \displaystyle{AD·DC·DD_1\over6} = {666\over6} = 111}\\$ 

Ответ: 111