Найдите корень уравнения
log2(х−3)=6\log_2 (х-3) =6log2(х−3)=6
\log_2 (х-3) =6,log2(х−3)=6,
log2(х−3)=6∗log22\log_2 (х-3) =6*log_2 2 log2(х−3)=6∗log22
log2(х−3)=log226\log_2 (х-3) = \log_2 2^6 log2(х−3)=log226
(х−3)=26 (х-3) = 2^6 (х−3)=26
х−3=64 х-3 = 64х−3=64
x=64+3=67x=64+3=67x=64+3=67